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Rodolphe Bréard 2024-10-27 18:41:19 +01:00
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# Rust files
/.cargo
/target
**/*.rs.bk
Cargo.lock
# Backup files
*~
\#*
.\#*
*.swp

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[package]
name = "rust_job_scheduling"
version = "0.1.0"
authors = ["Rodolphe Breard <rodolphe@what.tf>"]
edition = "2021"
description = "Benchmark of several job scheduling algorithms implemented in Rust."
license = "MIT OR Apache-2.0"
publish = false
[dependencies]

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# Job scheduling. Using Rust.
Benchmark of several job scheduling algorithms implemented in Rust.
## The problem
We have a list of independent tasks that we want to execute as fast as
possible. In order to achieve this, we want to run then in parallel. However,
those tasks have different execution times that can vary from several orders of
magnitude. Fortunately, it is possible to estimate the execution time of each
task before running it.
The goal is therefore to schedule the execution of the tasks on all available
threads in such a way that minimizes the total running time. This is known as
the [optimal job scheduling problem][ojs problem] and can often be seen as a
[partition problem][part problem], which is known to be
[NP-complete][NP-complete].
[ojs problem]: https://en.wikipedia.org/wiki/Optimal_job_scheduling
[part problem]: https://en.wikipedia.org/wiki/Partition_problem
[NP-complete]: https://en.wikipedia.org/wiki/NP-completeness
### Example
If we have 4 tasks tasks to execute. Three of then takes 1 second each to
execute and the last one takes 3 seconds. We have 2 processing units of equal
power.
If each processing unit starts by executing one of the 1s tasks, they will both
finis this job after one second. Then, one of those processing unit will
execute the remaining 1s task while the other will execute the 3s task. At the
end, one processing unit would have ran 2 seconds and the other one 4 seconds.
The total time is therefore 4 seconds.
Instead, we could start having one processing unit to execute the 3s task and
the other one execute the three 1s task. At the end, both processing units
would have ran 3 seconds. The total time is therefore 3 seconds.
The second job scheduling was clearly better than the first one, resulting in
zero idling processing unit and therefore the shortest total execution time.
## Goal
Talking about job scheduling algorithms and all the cool stuff you can use to
implement them in an efficient way is one thing. Actually implementing them and
gathering data on how it actually went in a real situation is another.
This project choses the later and therefore aims to implement several of those
algorithms in Rust and benchmark them. Let the battle begin.

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hard_tabs = true

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